1.

The relative rates of effusion of O_(2) to CH_(4) througha containe containing O_(2) and CH_(4) in 3 : 2 mass ratio will be-

Answer»

`(3sqrt(2))/(4)`
`(3)/(4sqrt(2))`
`(3)/(2sqrt(2))`
None of these

Solution :`{:(pi PROP (n)/(sqrt(Mw)) , n = "MOLE"),(,M_(w)=mol.mass):}`
`(r_(O_(2)))/(r_(Ch_(4)))= ((3)/(32sqrt(32)))/((2)/(16sqrt(16)))=3/(4sqrt(2))`


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