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The remainder obtained when t6 + 3t2 + 10 is divided by t3 + 1 is |
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Answer» when we find the zero of the POLYNOMIAL p(x)=t^6+3t^2+10g(x)=t^3+1 t^3+1=0t^3=-1t=cube ROOT of -1 =-1now,p(-1)=(-1)^6+3(-1)^2+10=1+3+10=14is right MARK as brainliest plzz |
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