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The remainder when `27^(10)+7^(51)` is divided by `10`A. `4`B. `6`C. `9`D. `2` |
Answer» Correct Answer - D `(d)` `(27)^(10)+7^(51)=(30-3)^(10)+(10-3)^(51)` `=3^(10)-3^(51)+10lambda` `=(10-1)^(5)-3(10-1)^(25)+10lambda` `=-1+3+10lambda_(1)` `=2+10lambda_(1)` `:.` Remainder is `2` |
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