The remainder when the square of any prime number greater than 3 is di

1.	The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2
Answer» Answer: The remainder when the SQUARE of any prime number GREATER than 3 is divided by 6, is (Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a NATURAL number and (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1 c is the correct answer

The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2

Answer»

Answer:

The remainder when the SQUARE of any prime number GREATER than 3 is divided by 6, is

(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a NATURAL number

and (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1

c is the correct answer

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The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2​

c is the correct answer

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The remainder when the square of any prime number greater than 3 is divided by 6, is(Hint: Any prime number greater than 3 is of the form 6k + 1, where k is a natural numberand (6k + 1)2 = 36k2 + 12k +1 = 6k(6k+2)+1)a) 1b) 3c) 4d) 2