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The remainder when the square of any prime number greater than 3 is divided by 6, isA. 1B. 3C. 2D. 4 |
Answer» Any prime number greater than 3 is of the form 6k ± 1, where k is a natural number and (6k ± 1)2 = 36k2 ± 12k + 1 = 6k (6k ± 2) + 1 Thus, the remainder is 1. |
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