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The required section modulus of the channel/I-section purlin can be determined by(a) Zpz = Myγm0/fy + (b/d)(Mzγm0/fy)(b) Zpz = Mzγm0/fy + (b/d)(Myγm0/fy)(c) Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy)(d) Zpz = Myγm0/fy + 2.5(b/d)(Mzγm0/fy)This question was posed to me in semester exam.The above asked question is from Purlins topic in chapter Design of Beams of Design of Steel Structures |
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Answer» RIGHT answer is (c) Zpz = Mzγm0/fy + 2.5(B/d)(Myγm0/fy) The EXPLANATION: The required section modulus of the PURLIN section can be DETERMINED by Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy ), where γm0 is partial safety factor for material = 1.1, d is depth of trial section, b is the breadth of the trial section, Mz and My are factored bending moments about Z and Y axes, respectively, and fy is yield stress of steel. Since the above equation involves b and d of a section, trial section must be used and from the above equation , it is checked whether chosen section is adequate or not. |
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