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The required section modulus of the channel/I-section purlin can be determined by(a) Zpz = Myγm0/fy + (b/d)(Mzγm0/fy)(b) Zpz = Mzγm0/fy + (b/d)(Myγm0/fy)(c) Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy)(d) Zpz = Myγm0/fy + 2.5(b/d)(Mzγm0/fy)This question was posed to me in semester exam.The above asked question is from Purlins topic in chapter Design of Beams of Design of Steel Structures

Answer» RIGHT answer is (c) Zpz = Mzγm0/fy + 2.5(B/d)(Myγm0/fy)

The EXPLANATION: The required section modulus of the PURLIN section can be DETERMINED by Zpz = Mzγm0/fy + 2.5(b/d)(Myγm0/fy ), where γm0 is partial safety factor for material = 1.1, d is depth of trial section, b is the breadth of the trial section, Mz and My are factored bending moments about Z and Y axes, respectively, and fy is yield stress of steel. Since the above equation involves b and d of a section, trial section must be used and from the above equation , it is checked whether chosen section is adequate or not.


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