1.

The resistance of 0.5 N solution of an electrolyte in a conductivity cell was found to be 25 ohm. Calculate the equivalent conductivity of the solution if the electrodes in the cell are 1.6 ci apart and have an area of 3.2 cm^2 ?

Answer»

` 10 S CM^2 eq^(-1)`
`15 cm^(2) eq^(-1)`
`20 S cm^(2) eq^(-1)`
`40 S cm^(2) E`

Solution :`40 S cm^(2) e`


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