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The resistance of a conductor `R = V//I`, where `V = (50 +- 2) V` and `I = (9 +- 0.3) A`. Find the percentage error in `R`. |
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Answer» `(Delta R)/(R ) = (Delta V)/(V) + (Delta I)/(I)` `= (2)/(50) + (0.3)/(9)` `(Delta R)/(R ) xx 100 = ((2)/(50) + (0.3)/(9)) xx 100` `= 4 + 3.3` `= 7.3%` |
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