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The resistance of a copper wire of length 5 m is 0.5 Omega. If the diameter of the wire is 0.05 cm, determine its specific resistance. |
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Answer» SOLUTION :`rho = (RA)/(L )` or ` R = (rho l )/(A)` `A = PI r ^(2) = 3. 14 xx (2. 5 xx 10 ^(-4))^(2)` ` = 1. 96 25 xx 10 ^(-7) m ^(2)` `rho = (0.5 xx 1. 9625 xx 10 ^(-7))/( 5)` `rho = 1. 9625 xx 10 ^(-8) Omega -m` |
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