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The resistance of a decinormal solution of an electrolyte in a conductivity cell was found to be 245 ohms. Calculate the equivalent conductivity of the solution if the electrodes in the cell were 2 cm apart and each had an area of 3.5 sq. cm.

Answer»


Solution :`kappa=Gxx(l)/(a)=(1)/(R)XX(l)/(a)=(1)/(245Omega)xx(2CM)/(3.5cm^(2))`
`wedge_(eq)=kappaxx(1000)/("Normality")=((1)/(245)xx(2)/(3.5)OMEGA^(-1)cm^(-1))xx(1000cm^(3)L^(-1))/(0.1molL^(-1))=23.32Omega^(-1)cm^(2)eq^(-1)`


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