1.

The resistance of a galvanometer is 50 ohm and the maximum current which can be passed throughit is 0.002 A. What resistance must be connected to it in order to convert it into an ammeter of range0 – 0.5 A?

Answer»

0.02 ohm
0.002 ohm
0.2 ohm
0.5 ohm

Solution :`(I - I_(G)) XX S = I_(g) G,S = ((0.002 xx 50)/(0.5 - 0.002)) = 0.2 OMEGA`


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