The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-0*5) V and current in resistance, I=(4+-0*2)A. And current in resistance with its percentage error :

The resistance of a metal is given by R=(V)/(I), where V is potential

1.	The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-05) V and current in resistance, I=(4+-02)A. And current in resistance with its percentage error :
Answer» `(2+-56%)` ohm `(2+-07%)` ohm `(2+-35%)` ohm `(2+-1125%)` ohm Solution :`R=(V)/(I)=(8)/(4)=2ohm.` `(DeltaR)/(R)xx100=(DELTAV)/(V)xx100+(DeltaI)/(I)xx100` `=(05)/(8)xx100+(02)/(4)xx100=1125%` `:.R=(2+-11*25)OMEGA.` HENCE correct CHOICE is `(d)`.

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The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-0*5) V and current in resistance, I=(4+-0*2)A. And current in resistance with its percentage error :

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The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-05) V and current in resistance, I=(4+-02)A. And current in resistance with its percentage error :