1.

The resistance of galvanomenter is G and its current capacity is I_(g). To increase the current capacity by 'n' times, the required value of shunt is ______ .

Answer»

`G/(n-1)`
`(I_(g)*G)/(n-1)`
`(NG)/(n-1)`
`(I_(g)*G)/(I-n*I_(g))`

SOLUTION :`I=nI_(g)`
`S=(I_(g)G)/(I-I_(g))=(I_(g)G)/(nI_(g)-I_(g))=G/(n-1)`


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