1.

The resistance of moving coil galvanometer is made twice its original value in order to increase current sensitivity by 50% Will the voltage sensitivity change ? If so, by how much?

Answer»

Solution :Yesvoltagesensitvitywill change .
Voltagesensitivity is `V_(s) = (I_(s))/(R)`
WHENTHE RESISTANCEIS doubled,then newresistanceis `R = 2R`
INCREASE incurrentsensitivity is `V_(S) = ((3)/(2) I_(s))/(2R) = (3)/(4)V_(s)` .
Hence ,the voltagesensitivitydecreases .The percentagedecrease in voltagesensitivityis `(V_(s) - V_(s))/(V) XX 100% = 25%` .


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