1.

The resistance of the bulb filament is 100at a temperature of 100^(@)C. If its temperature coefficient of resistance be 0.005 per ^(@)C, its resistance will become200 Omegaat a temperature

Answer»

`200^(@)C`
`500^(@)C`
`400^(@)C`
`300^(@)C`

Solution :`R_(2)= R_(1) (1 + ALPHA (T_(2)-T_(1)))`
`200= 100 (1 + 0.005) (T_(2)-100)`
`T_(2)= 300`


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