1.

The resonant frequency of a circuit is f. If the capacitance is made 4 times the initial values, then the resonant frequency will become ……

Answer»

`f/2`
2f
f
`4/f`

Solution :`omega=1/sqrt(LC)`
In `2pif 1/sqrt(LC) 2PI` and L equal
`THEREFORE f prop 1/sqrtC`
`therefore (f_2)/(f_1)=sqrt(C_1/C_2)=sqrt(C/(4C))=1/2`
`therefore f_2=f_1/2` but `f_1=f`
`therefore f_2=f/2`


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