The resultant of P and Q is perpendicular to P. what is the angle betw

1.	The resultant of P and Q is perpendicular to P. what is the angle between P & Q?(a) cos-1 (P/Q)(b) cos-1 (-P/Q)(c) sin-1 (P/Q)(d) sin-1 (-P/Q)
Answer» Answer is (b) cos^-1 (-P/Q) tan β = Q sinθ/(P + Q cosθ), here β = 90°. Hence P + Q cosθ = 0, Hence θ = cos^-1(-P/Q)

The resultant of P and Q is perpendicular to P. what is the angle between P & Q?(a) cos-1 (P/Q)(b) cos-1 (-P/Q)(c) sin-1 (P/Q)(d) sin-1 (-P/Q)

Answer»

Answer is (b) cos^-1 (-P/Q)

tan β = Q sinθ/(P + Q cosθ), here β = 90°.

Hence P + Q cosθ = 0, Hence θ = cos^-1(-P/Q)

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The resultant of P and Q is perpendicular to P. what is the angle between P &amp; Q?(a) cos-1 (P/Q)(b) cos-1 (-P/Q)(c) sin-1 (P/Q)(d) sin-1 (-P/Q)

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The resultant of P and Q is perpendicular to P. what is the angle between P & Q?(a) cos-1 (P/Q)(b) cos-1 (-P/Q)(c) sin-1 (P/Q)(d) sin-1 (-P/Q)