1.

The resultant of the system in the figure is a force of 8 N parallel to the given force through R. The value of PR equals to?

Answer»

`1/(4RQ)`
`3/(8RQ)`
`3/(5RQ)`
`2/(5RQ)`

Solution :(3) By TAKING MOMENT of force about POINT R,`5xxPR-3xxRQ=0rArrPR=3/5RQ`.


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