1.

The resultant of two forces acting at an angle of 120° is 10 kg wt and is perpendicular to one of the forces. That force is :

Answer»

`10sqrt(3)`KG wt
`20sqrt(3)` kg wt
10 kg wt
`10/sqrt(3)` kg wt

Solution :Let two forces be `vec(F_(1))` and `vec(F_(2))` inclined at an ANGLE `THETA = 120°`. Since resultant force is 10 kg wt and perpendicular to `vec(F_(1))` . So `vec(F_(2))` makes angle with `vec(F)`

`:.F_(2)COS30^@=F`
`F_(2)10/(cos30^@)=(10xx2)/sqrt(3)=20/sqrt(3)kg wt`
Also `F_(2)sin30^@=F_(1)`
`:.F_(1)=20/sqrt(3)xx1/2=10/sqrt(3)`


Discussion

No Comment Found

Related InterviewSolutions