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The resultant of two forces is 20 N when one of force is 20sqrt(3) N and angle between two forces is 30° then what is value of second force ? |
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Answer» 10N `(20)^(2)=(20sqrt(3))^(2) +B^(2)+2xx20sqrt(3)Bxxsqrt(3)/2` `(20)^(2)=1200+B^(2)+20sqrt(9)B` `-800=B^(2)+60B` or `B^(2)+60B+800=0` SOLVING the quadratic equation B = 20 N |
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