1.

The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from zero to maximum value and the peak value will beA. `2 xx 10^(-2)` sec and 14.14 ampB. `1 xx 10^(-2)` sec and 7.07 ampC. `5 xx 10^(-3)` sec and 7.07 ampD. `5 xx 10^(-3)` sec and 14.14 amp

Answer» Correct Answer - D
`l_("rms") = 10 A implies l_(o) = 10sqrt(2) A = 14.14` Amp
Let `I = 0` when `t = 0`.
`:. l = l_(o) sin omega t`
`l_(o) = l_(o) sin omega t implies omega t = (pi)/(2)`
`implies t = (pi)/(2 omega) = (pi)/(2 xx 2pi xx f) = (1)/(200) = 5 xx 10^(-3) sec`


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