1.

The rms value of an ac of 50Hz is 10A. The time taken be an alternating current in reaching from zero to maximum value and the peak value will beA. `2xx10^(-2) s and 14.14 A`B. `1xx10^(-2) s and 7.07 A`C. `5xx10^(-3) s and 7.07 A`D. `5xx10^(-3) s and 14.14 A`

Answer» Correct Answer - D
Time for reaching maximum of peak value form 0
`(T)/(4) =(1)/(4)xx(1)/(500 s)=1/200 s =5xx10^(-3)s`
`(I_0)=10 sqrt(2) A =14.14 A`


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