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The root mean square speed of hydrogen is `sqrt(5)` times than that of nitrogen. If T is the temperature of the gas, then :A. `T_(H_(2))=T_(N_(2)`B. `T_(H_(2))gtT_(N_(2)`C. `T_(H_(2))ltT_(N_(2)`D. `T_(H_(2))=sqrt(7)T_(N_(2)` |
Answer» Correct Answer - c (c) `U_("rms")=sqrt((3RT)/(Mw))=((U_("rms"))_(H_(2)))/((U_("rms"))_(N_(2)))=sqrt(T_(H_(2))/(M_(H_(2)))xxM_(N_(2))/(T_(N_(2)))),` `(U_("rms"))_(H_(2))=sqrt(5)(U_("rms"))_(N_(2))` `:.((U_("rms"))_(H_(2)))/((U_("rms"))_(H_(2)))xxsqrt(5)=sqrt(T_(H_(2))/(T_(N_(2)))xx(28)/(2))` `=(sqrt(5))/(1)=sqrt(T_(H_(2))/(T_(N_(2)))xx14)` `=5=T_(H_(2))/(T_(N_(2)))xx14` `T_(N_(2))xx5=T_(H_(2))xx14` `:. " "T_(N_(2))gtT_(H_(2))` |
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