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The root mean square speed of hydrogen is `sqrt(5)` times than that of nitrogen. If T is the temperature of the gas, then :A. `T_(H_(2))=T_(N_(2))`B. `T_(H_(2)) gt T_(N_(2))`C. `T_(H_(2))lt T_(N_(2))`D. `T_(H_(2)) lt sqrt(7)T_(N_(2))` |
Answer» Correct Answer - 3 `V_(rms)=sqrt((3RT)/(M))=((V_(rms))_(H_(2)))/((V_(rms))N_(2))=sqrt((T_(H_(2)))/(M_(H_(2)))xx(M_(N_(2)))/(T_(N_(2)))),` `(V_(rms))H_(2)=sqrt(5)(V_(rms))N_(2)` `((V_(rms))H_(2))/((V_(rms)N_(2)))xxsqrt(5)=sqrt((T_(H_(2)))/(M_(H_(2)))xx(M_(N_(2)))/(T_(N_(2)))),` `(sqrt(5))/(1)=sqrt((T_(H_(2)))/(T_(N_(2)))xx14)` `5=(T_(H_(2)))/(T_(N_(2)))xx14` `T_(N_(2))xx5=T_(H_(2))xx14` `T_(N_(2))gtT_(H_(2))` |
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