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The root mean square velocity of the molecules in a sample of helium is `5//7th` that of the molecules in a sample of hydrogen. If the temperature of hydrogen sample is `0^(@)C`, then the temperature of the helium sample is aboutA. `0^(@)C`B. `0 K`C. `273^(@)C`D. `100^(@)C` |
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Answer» Correct Answer - A `((v_(rms))_(He))/((v_(rms))_(H_(2))) = sqrt(T_(He)/T_(H_(2)).((M_(0))_(H_(2)))/((M_(0))_(He)))` `5/7=sqrt(T_(He)/((0+273)).2/4)=sqrt(T_(He)/546)` `T_(He) = ((5)/(7))^(2) xx 546 = 278.6 K` `= 278.6 - 273 = 5.6^(@)C cong 0^(@)C` |
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