1.

The roots of a quadratic eq x square minus 4root2x plus 6​

Answer»

ANSWER:

GIVEN QUADRATIC equation:

x²-4√2x+6=0

=> x²-4√2x = -6

=> x²-2*x*2√2 = -6

=> x²-2*x*2√2+(2√2)²=-6+(2√2)²

=> (x-2√2)² = -6 + 8

=> (x-2√2)² = 2

=> x-2√2 = ±2

=> x = 2√2 ± 2

=> x = 2(√2±1)

THEREFORE,

x = 2(√2+1) or x = 2(√2-1)


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