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The roots of the equation `4x^2-2sqrt5 x +1=0` are .A. `sin36^(@),sin18^(@)`B. `sin18^(@),cos36^(@)`C. `sin36^(@),cos18^(@)`D. `cos 18^(@),cos36^(@)` |
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Answer» Correct Answer - B `4x^(2)-2sqrt(5)x+1=0` `therefore x=(2sqrt(5)+-2)/(8)=(sqrt(5)+-1)/(4)` `therefore` Roots are `sin 18^(@)` and `cos36^(@)` |
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