InterviewSolution
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InterviewSolution
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The roots of the equation `t^3+3a t^2+3b t+c=0a r ez_1, z_2, z_3`which represent the vertices of an equilateral triangle. Then`a^2=3b`b. `b^2=a`c. `a^2=b`d. `b^2=3a`A. `a^(2) = 3b`B. `b^(2) = a`C. `a^(2) = a`D. `b^(2) = 3a` |
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Answer» Correct Answer - C `S_(1)=Sigmaz_(1)=-3a,S_(2)=Sigmaz_(1)z_(2)=3b` `Sigmaz_(1)^(2)=Sigmaz_(1)z_(2)` `rArr (Sigmaz_(1))^(2)-2Sigmaz_(1)z_(2)=Sigmaz_(1)z_(2)` `rArr (Sigmaz_(1))^(2)=3Sigmaz_(1)z_(2)` `rArr (-3a)^(2)=3(3b)` `rArr a^(2)=b` |
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