InterviewSolution
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InterviewSolution
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The roots of the equation `x^(4)-2x^(2)+4=0` are the vertices of `a` :A. square inscribed in a circle of radius `2`B. rectangle inscribed in a circle of radius `2`C. square inscribed in a circle of radius `sqrt(2)`D. rectangle inscribed in a circle of radius `sqrt(2)` |
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Answer» Correct Answer - D `(d)` `x^(4)-2x^(2)+4=0` `impliesx^(2)=1+-sqrt(3)i` `=2e^(+-(pi)/(3))` `implies x=+-sqrt(2)e^(+-i(pi)/(6))` These points lie on a circle of radius `sqrt(2)`, as the diagonals intersect at an angle `pi//3`, `:.` These are the vertices of an inscribed rectangle. |
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