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The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. then, its angular momentum will beA. `sqrt(E )/(mr^(2))`B. `(E )/(2mr^(2))`C. `sqrt(2 Emr^(2))`D. `sqrt(2 Emr)` |
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Answer» Correct Answer - C If m is the mass and v is the orbital velocity of the satellite then its kinetic energy `E=1/2 mv^(2) rarr Em =1/2 m^(2)v^(2)` or `m^(2)v^(2)=2Em` `rarr mv=sqrt(2Em)` if r is the radius of the orbit of the satellite then its angular momentum L= mvr using Eq i we get `L=sqrt(2Em) r=sqrt(2Emr^(2))` |
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