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The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. then, its angular momentum will beA. `sqrt(2Emr)`B. `sqrt(2Emr^(2))`C. `sqrt((E )/(mr^(2)))`D. `(E )/(2mr^(2))` |
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Answer» Correct Answer - B `E=(1)/(2)mv^(2) " " therefore 2E = mv^(2) " " therefore 2Em = m^(2)v^(2)` `therefore` Linear momentum `(p)=mv=sqrt(2Em) " "` ….(1) `therefore` Angular momentum (L) of the satellite `= mvr = sqrt(2Em). R = sqrt(2Emr^(2))` |
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