1.

The self inductance angle of a solenoid of length and are of cross section A with a fixed number of turns N increases as,

Answer»

l and A increase
l decreases and A increases
l increases and A decreases
both l and A decreases

Solution :Here `L=mu_0n^2Al`
`=mu_0(N/l)^2Al`
`=(mu_0N^2Al)/l^2`
`THEREFORE L=(mu_0N^2A)/l`
When N= constant SELF inductance L will increase by decreasing l and by INCREASING A.


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