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The self-inductance of a coil having 200turns is 10 millihenry. Calculate the magnetic flux through the cross-section of the coil corresponding to current of 4 milliampere. Also determine the total flux linked with the coil. |
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Answer» SOLUTION :Total magnetic flux LINKED with the coil, `phi= LI= 10^(-2) H xx 4 xx 10^(-3)A` `phi= 4 xx 10^(-5)Wb` Magnetic flux through the cross-section `=(phi)/(200) = 2 xx 10^(-7)Wb` |
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