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The self-inductance of an air-core solenoid is 4.8 mH. If its core is replaced by iron core, then its self-inductance becomes 1.8 H. Find out the relative permeability of iron. |
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Answer» Solution :`L_(AIR)=4.8xx10^(-3)H` `L_(iron)`=1.8H `L_(air)=mu_(0)N^(2)Al=4.8xx10^(-3)H` `THEREFORE``mu_(r)=(L_(iron))/(L_(iron))=(1.8)/(4.8xx10^(-3))`=375 |
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