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The semi vertical angle of the cone of the rays of light incident on the objective of a microscope is 20^(@). If the wavelength of incident light is 6000Å, calculate the smallest distance between two points which can be just resolved. |
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Answer» Solution :Data: `i_("max") = 20^(@), lambda= 6 xx 10^(-7)m, n=1` (air) Numerical APERTURE, `NA=nsini_("max")= 1XX SIN20^(@) = 0.34420` The limit of resolution (for illuminated OBJECTS), `d_("min") = lambda/(2NA) = (6 xx 10^(-7))/(2 xx 0.3420) = 8.772 xx 10^(-7)`m The limit of resolution (for self-luminous objects), `d_("min") = (1.22lambda)/(2NA) = 1.22 xx 8.772 xx 10^(-7) = 1.053 xx 10^(-6)`m |
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