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The series combination of resistance R and inductance L is connected to an alternating source of e.m.f. e = 311 sin (100 πt). If the value of wattless current is 0.5A and the impedance of the circuit is 311Ω, the power factor will be –

Answer» The series combination of resistance R and inductance L is connected to an alternating source of e.m.f. e = 311 sin (100 πt). If the value of wattless current is 0.5A and the impedance of the circuit is 311Ω, the power factor will be –


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