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The series corresponding to minimum wavelength transition in H atom ......

Answer»

Balmer
LYMAN
Paschen
Brackett

Solution :Lyman series is obtained when an electron jumps to the first orbit (N = 1) from any OUTER orbit`(n_(2)=2,3,4...)`
`(1)/(lambda)=Rz[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
For H, Z = 1 and R is the Rydberg.s CONSTANT `R= 1.097 xx 10^(7) m^(-1)`. In this series the shortest wavelength or the limit of this series for `n_(1)=1 and n_(2), =OO lambda=911 Å`


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