1.

The short wavelength limit for the Lyman series of the hydrogen spectrum is 913.4 Å. Calculate the short wavelength limit for Balmer series of the hydrogen spectrum.

Answer»

Solution :As PER question `(1)/((lambda_("limit"))_("Lyman")) = R [(1)/((1)^(2)) - (1)/((oo)^(2))] = R = 913.4 Å`
and `""(1)/((lambda_("limit"))_("BALMER")) =R [(1)/((2)^(2)) - (1)/((oo)^(2))] = (R)/(4) `
`rArr""(lambda_("limit"))_("Balmer") = 4 (lambda_("limit"))_("Lyman") = 4 XX 913.4 Å = 3653.6 Å`


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