1.

The shortest wave lengths of Paschen, Balmer and Lymann series are in the ratio :

Answer»

`9:1:4`
`1:4:9`
`9:4:1`
`1:9:4`

Solution :`1/lambda =R_(H) [1/n_(1)^(2)-1/n_(2)^(2)], n_(2)=oo" in each case"`
For Paschen `n_(1)=3`
For Balmer `n_(1)=2`
For Lyman `n_(1)=1`
`lambda_(P): lambda_(B) : lambda_(L)=9:4:1`


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