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The shortest wavelength in the Lyman series is 911.6Å. Then the longest wavelength in Lyman series is ...... |
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Answer» `1215Å` `:.(1)/(lamda_(min))=R[(1)/(1^(2))-(1)/(oo^(2))]` `:.(1)/(lamda_(min))=R""......(1)` `[:.(1)/(oo^(2))=0]` For maximum wavelength n = 2, `(1)/(lamda_(min))=R[(1)/(l^(2))-(1)/(2^(2))]` `=R[(1)/(l)-(1)/(4)]` `(1)/(lamda_(max))=(3R)/(4)""......(2)` `:.(lamda_(max))/(lamda_(min))=(R)/((3R)/(4))` Taking RATIO of equation (1) and (2), `:.lamda_(max)=(4)/(3)xxlamda_(min)` `=(4)/(3)xx911.6Å` `=4xx303.9=1215.6Å` `:.lamda_(max)=1215Å` (Taking near by value in integer) |
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