1.

The shortest wavelength in the Lyman series of hydrogen spectrum is 912 Å corresponding to a photon energy of 13.6 eV. The shortest wavelength in the Balmer series is about

Answer»

3648Å
8208Å
1228Å
6566Å

Solution :In Lyman series `(lambda_("min"))_(L)=1/R and (lambda_("min"))_(B)=4/R`
`rArr (lambda_("min"))_(B)=4 xx (lambda_("min"))_(L)=4 xx 912=3648Å`


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