

InterviewSolution
Saved Bookmarks
1. |
The shortest wavelength of the Brackett series of a hydrogen-like atom (atomic number of `Z` ) is the same as the shortest wavelength of the Balmer series of hydrogen atom. The value of `z` isA. 4B. 2C. 3D. 6 |
Answer» Correct Answer - B `R [(1)/(1^(2)) - (1)/(oo^(2))] = R Z^(2) [(1)/(2^(2)) - (1)/(oo^(2))] or Z = 2` |
|