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The shortest wavelength of the spectrum line is that of electron being transits into atom to ion from n = 2 to n = 1 for ....... |
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Answer» hydrogen atom `(1)/(lamda)=RZ^(2)[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]` R and `(1)/(n_(f)^(2))-(1)/(n_(f)^(2))` are constant `:.(1)/(lamda)propZ^(2)` and Z = 3 is maximum for doubly ionized lithium in a given atom. |
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