The side BC of a triangle ABC is produced to D . the bisector angle A meets BC at E prove that angle ABC+ANGLE ACD = 2

The side BC of a triangle ABC is produced to D . the bisector angle A

1.	The side BC of a triangle ABC is produced to D . the bisector angle A meets BC at E prove that angle ABC+ANGLE ACD = 2
Answer» -step explanation:searchWhat WOULD you LIKE to ask?7thMathsThe Triangle and Its PropertiesExterior Angle of a TriangleThe side BC of a ABC is pr...MATHSavatarAsked on December 26, 2019 byPious RatheeThe side BC of a △ABC is produced, such that D is on ray BC. The BISECTOR of ∠A meets BC in ∠ as. SHOWN in the figure. PROVE that ∠ABC+∠ACD=2∠ALC.1048993HARDShareStudy laterANSWERInΔABLlet∠BAL=a&∠BA=bexterior∠ALC=∠BAL+∠LBA=a+bInΔABCALbisect∠BAC&∠AC=aexterior∠ACD=∠BAC+∠ABC=2a+b=∠ABC+∠ACo=b+(2a+b)=2a+2b=2(a+b)=2∠ALC