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The side of a square is equal to height of a triangle. If the area of the triangle is 294 m? and the respective ratio of its height and base is 3 : 4, what is the perimeter of the square (in m) ?1). 1082). 963). 844). 72 |
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Answer» Solution Let HEIGHT of triangle = $3x$ => Base of triangle = $4x$ => Area of triangle = $\frac{1}{2} \times 3x \times 4x = 294$ => $6x^2 = 294$ => $x^2 = \frac{294}{6} = 49$ => $x = \sqrt{49} = 7$ => Height of triangle = $3 \times 7 = 21$ m Also, side of square = height of triangle = 21 m $\therefore$ Perimeter of square = $4 \times 21$ = $84$ m |
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