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The sides of a rectangle are in the ratio 3:7 and its area is 1029m^2. find the deminsions of the rectangle and then find its perimetre​

Answer» LET length be 7X and BREADTH be 3x.Area= 7x × 3x 21x^2Now, 21x^2=1029 X^2 = 1029/21 X^2 = 49 X = √49 =7Now,Length= 7x = 7×7= 49mBreadth= 3x = 3×7 = 21mNow,Perimeter = 2(l+b) = 2(49+21) = 2×70 = 140m Ans.


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