1.

The sides of a triangle are 35 cm, 54 cm and 61 cm respectively. Find thelength of its longest altitude.​

Answer»

Step-by-step explanation:

s=

2

a+b+c

=

2

35+54+61

=75

Area, A=

s(s−a)(s−b)(s−c)

=

75(75−35)(75−54)(75−61)

=420

5

cm

2

Now, Area of the TRIANGLE is ALSO given as A=

2

1

×a×h

Where, h is the longest altitude.

Therefore,

2

1

×a×h=420

5

Hence, h=24

5

cm


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