The sides of triangle are 25cm, 29cm and 56cm.Find the altitude of lon

1.	The sides of triangle are 25cm, 29cm and 56cm.Find the altitude of longest side. (with explaination.)
Answer» ${\huge{\underline{\underline{\sf{\pink{Solutions:-}}}}}}$ ═══════════════════════════════ First We Find the area :- $<klux>AREA</klux> = \sqrt{s(s - a)(s - b)(s - c)}$ = (25 + 39 + 56) ÷ 2 = 60 $= \sqrt{(60)(60-25)(60-39)(60-56)}$ $= \sqrt{176400}$ = 420 cm² ════════════════════════════════ Now we Find the Altitude $Area = \frac{1}{2} \times base \times height$ $420 = \frac{1}{2} \times 56 \times h$ 420 = 28 x height height = 420\28 height = 15 cm The altitude is 15cm.