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The simplified value of `(sec x+secy+tanx tany)^(2)-(sec x tany+tanyx secy)^(2)`A. `-1`B. 0C. `sec^(2)x`D. 1 |
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Answer» Correct Answer - d `(secx secy+tanxtany)^(2)` `-(secx tany+tanx secy)^(2)` `=sec^(2)x.sec^(2)y+tan^(2) x.tan^(2)y+2secx.secy.tanx.tany-sec^(2)x` `tan^(2)y-tan^(3) x,sec^(2)y+2secx.tany.tanx.secy` `=sec^(2)x[ s e c^(2)y-tan^(2)x]-tan^(2)x [sec^(2)y-tan^(2)y)` ` =(sec^(2)x-tan^(20x)(sec^(2)y-tan^(2)y)` `=1xx1=1` |
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