The slits in Young's double slit experiment are 0.5 mm apart and interference pattern is observed on a screen distant 100 cm from the slits. It is found that the 9th bright fringe is at a distance of 8.835 mm. From the second dark fringe. The wavelength of light will be :

The slits in Young's double slit experiment are 0.5 mm apart and inter

1.	The slits in Young's double slit experiment are 0.5 mm apart and interference pattern is observed on a screen distant 100 cm from the slits. It is found that the 9th bright fringe is at a distance of 8.835 mm. From the second dark fringe. The wavelength of light will be :
Answer» `7529 Å` `6253 Å` `6779 Å` `5890 Å` SOLUTION :`(9D)/(d) (LAMBDA) - 3/2 .(D)/(d)(lambda) = (15)/(2).(D)/(d) lambda = 8.835 xx 10^(-3)` SOLVING, `lambda = 5890 Å`

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The slits in Young's double slit experiment are 0.5 mm apart and interference pattern is observed on a screen distant 100 cm from the slits. It is found that the 9th bright fringe is at a distance of 8.835 mm. From the second dark fringe. The wavelength of light will be :

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